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Secondary Math I · Module 3 · Features of Functions

3.4 — The Water Park

Supplement for Mathematics Vision Project (MVP) curriculum · Secondary Math I, Module 3, Section 3.4
Independently created to support students using MVP Math. Not official publisher material and not affiliated with or endorsed by the Mathematics Vision Project.

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1. In class: A Solidify Understanding Task

From the draining pools to their equations

In your MVP packetSection 3.4 · Main task · pp. 16–17 · Problems 1–3 and 6

Read the pool graph, use the pumping information to label it, and write each draining rule.

Aly and Dayne work at a water park. They each pump water out of a pool, starting at the same time. Let \(x\) be the number of minutes since they started. The amount left in Aly’s pool is \(a(x)\), and the amount left in Dayne’s is \(d(x)\), measured in gallons.

The packet’s graph has time on the horizontal axis and water remaining on the vertical axis. Both lines slope downward: as time passes, less water remains. Each line is straight, so each pump removes water at a constant rate.

The packet’s starting graph, with unnumbered axes: Aly starts with more water and drains faster; Dayne empties later.a(x)d(x)Time (minutes)Amount of water (gallons)
Starting graph from the MVP activity, recreated with the axes still unnumbered.

Even before numbering the axes, you can read four things: Aly starts with more water; her line falls more steeply, so her pump drains faster; her pool empties first; and the crossing shows a time when the pools have equal amounts.

Worked example 1 — Write Dayne’s draining rule

Dayne’s pump removes 1,000 gallons per minute and empties his pool in 24 minutes. That tells us how much water was there at the start:

\[1000\times24=24{,}000\text{ gallons}.\]

After \(x\) minutes, the pump has removed \(1000x\) gallons. Subtract that amount from the starting amount:

\[\boxed{d(x)=24{,}000-1000x}.\]

The constant 24,000 is the initial amount. The coefficient −1,000 is the change in water amount per minute. At \(x=0\), the graph is at \((0,24{,}000)\); at \(x=24\), it reaches \((24,0)\).

These two points let us number the original graph. Dayne’s time intercept is 24 minutes, and his water intercept is 24,000 gallons. Count the equal spaces from zero to each intercept to establish the scale on that axis.

Worked example 2 — Write Aly’s draining rule

On the newly labeled packet graph, Aly starts with 28,000 gallons and empties her pool in 20 minutes. Her pumping rate is

\[\frac{28{,}000}{20}=1400\text{ gallons per minute}.\]

After \(x\) minutes, 1,400 gallons have been removed for each minute elapsed. Her rule is therefore

\[\boxed{a(x)=28{,}000-1400x}.\]

Check the endpoints: \(a(0)=28{,}000\), and \(a(20)=28{,}000-1400(20)=0\).

Aly and Dayne drain their poolsAly begins with 28,000 gallons and empties her pool after 20 minutes. Dayne begins with 24,000 gallons and empties his pool after 24 minutes. Their graphs intersect at 10 minutes and 14,000 gallons. Each grid column represents 3 minutes and each grid row represents 4,000 gallons.0369121518212404,0008,00012,00016,00020,00024,00028,00032,000Water remaining (gallons)Time x (minutes)(10, 14,000)a(x): Alyd(x): Dayne
The packet’s water-park example, redrawn with numbered axes. Aly’s pool empties after 20 minutes; Dayne’s empties after 24 minutes.

Use function notation to find an amount or a time

In your MVP packetSection 3.4 · Main task · p. 17 · Problems 8–9

Distinguish a known input from a known output, then interpret the result in the pool situation.

Read \(a(x)\) as “a of x.” The letter \(a\) names Aly’s function; the number in parentheses tells you which input to use. The whole expression gives the output, in gallons. Thus \(a(5)\) is the amount in Aly’s pool after 5 minutes.

Worked example 3 — Find the amount in Aly’s pool after 5 minutes

To find \(a(5)\), substitute 5 for \(x\):

\[\begin{aligned}a(5)&=28{,}000-1400(5)\\&=28{,}000-7000\\&=21{,}000.\end{aligned}\]

After 5 minutes, Aly’s pool contains 21,000 gallons. The corresponding point on her graph is \((5,21{,}000)\).

In \(d(x)=2000\), the output is known: Dayne’s pool contains 2,000 gallons. The input—the time—is what we need to find.

Worked example 4 — Find when Dayne’s pool has 2,000 gallons remaining

Replace \(d(x)\) with its rule and solve for \(x\):

\[\begin{aligned}24{,}000-1000x&=2000\\-1000x&=-22{,}000\\x&=22.\end{aligned}\]

Dayne’s pool contains 2,000 gallons after 22 minutes. Check: \(d(22)=24{,}000-22{,}000=2000\). On the graph, you could find the same time by starting at 2,000 gallons on the vertical axis, moving across to Dayne’s line, then down to the time axis.

Limit the equations to the draining situation

In your MVP packetSection 3.4 · Main task · p. 17 · Problems 4–6

State the domain and range, accounting for the beginning and end of draining.

The domain describes the allowed times; the range describes the amounts of water reached. Time begins at 0, and draining ends when each pool is empty. Fractional minutes are allowed.

Domains and ranges for the pools
  • Dayne: domain \([0,24]\) minutes; range \([0,24{,}000]\) gallons.
  • Aly: domain \([0,20]\) minutes; range \([0,28{,}000]\) gallons.

The brackets include both endpoints: the starting amount and the empty pool are part of the process. Write each range from the smaller amount to the larger, even though the pool is draining.

As an unrestricted linear function, \(a(x)=28{,}000-1400x\) has domain and range \((-\infty,\infty)\). The pool situation restricts those values: negative times are before the start, and times beyond 20 would give negative water amounts. For example, the formula gives \(a(22)=-2800\), but 22 is outside the draining model’s domain.

Compare the pools at the same time

In your MVP packetSection 3.4 · Main task · p. 17 · Problems 7 and 10

Interpret the intersection and the times when Aly’s pool contains more water.

At a given time, the higher line represents the pool with more water. The statement \(a(x)=d(x)\) means their amounts are equal at the same time; \(a(x)>d(x)\) means Aly’s amount is greater.

Worked example 5 — Read the intersection and compare the amounts

The two lines meet at \((10,14{,}000)\). After 10 minutes, both pools contain 14,000 gallons. Check that time in both equations:

\[\begin{aligned}a(10)&=28{,}000-1400(10)=14{,}000,\\d(10)&=24{,}000-1000(10)=14{,}000.\end{aligned}\]

Before the crossing, Aly’s line is above Dayne’s. Therefore \(a(x)>d(x)\) for \(0\le x<10\), written \([0,10)\) in interval notation. Include 0 because Aly starts with more water; exclude 10 because the amounts are equal then.

After the crossing, Aly’s line is below Dayne’s while both pools are draining. For example, at 12 minutes, \(a(12)=11{,}200\) and \(d(12)=12{,}000\): Dayne has more water left.

2. Ready — Compare linear and exponential functions

In your MVP packetSection 3.4 · Ready · p. 18 · Problem 1

Describe similarities and differences between linear and exponential functions.

This problem asks for a comparison in words: how the functions change, what their graphs look like, and which inputs and outputs they allow. Write your own comparison first, then use the sample answer below to check that you have included both similarities and differences.

Check your work — Ready 1 sample answer

Similarities: Both kinds of functions assign one output to each input. Both can describe an increasing or decreasing quantity, and both have a y-intercept. Their usual unrestricted forms allow all real inputs; a real situation may restrict that domain.

Differences in change and shape: A linear function has a straight graph and adds the same amount to its output for each one-unit increase in the input. An exponential function has a curved graph and multiplies its output by the same factor for each one-unit increase. For example, \(L(x)=6+2x\) adds 2 each step, while \(E(x)=6\cdot2^x\) doubles each step. Both begin at \((0,6)\).

Differences in outputs: An unrestricted nonconstant linear function has all real numbers in its range. For an exponential example such as \(y=6\cdot2^x\), the range is \((0,\infty)\): its outputs remain positive. Its graph approaches the x-axis without reaching it. A line can cross the x-axis; this exponential curve cannot.

3. Set — Read domain, range, and direction from a graph

In your MVP packetSection 3.4 · Set · pp. 18–19 · Problems 2–9

Give each graph’s domain, range, and increasing or decreasing behavior.

These are similar to the graph-reading problems in Sections 3.2 and 3.3. Use the interval explanation and endpoint example in Section 3.2 if you need a reminder about endpoints and interval notation. Try the problems yourself before opening the answer key.

Check your work — Set 2–9 answer key

The details matter: write each interval from the smaller number to the larger. Use a square bracket when an endpoint is included and a parenthesis when it is excluded. Always use parentheses with \(-\infty\) and \(\infty\).

  1. Domain: \([-5,2)\). Range: \((-6,5]\). Direction: decreasing.
  2. Domain: \((-\infty,4)\). Range: \((-6,-1)\). Direction: decreasing.
  3. Domain: \((-\infty,\infty)\). Range: \((-\infty,4)\). Direction: increasing.
  4. Domain: \([1,6]\). Range: \([-2,-1]\). Direction: increasing.
  5. Domain: \((-\infty,\infty)\). Range: \((-\infty,\infty)\). Direction: increasing.
  6. Domain: \([-5,\infty)\). Range: \([0.4,\infty)\), with the starting height estimated from the graph. Direction: increasing.
  7. Domain: \((-\infty,5]\). Range: \((-\infty,-1]\). Direction: increasing.
  8. Domain: \((-\infty,\infty)\). Range: \((0,\infty)\). Direction: decreasing.

4. Go — Write explicit and recursive sequence rules

In your MVP packetSection 3.4 · Go · p. 20 · Problems 10–18

Write explicit and recursive rules for the sequence tables.

These revisit the sequence rules from Section 3.2. Refer to its Go reminders if needed. Count steps in the index, not just rows in the table. Try each problem before checking the answers.

Check your work — Go 10–18 answer key

Recursive rules are given first. These answers start at each table’s first supplied index; equivalent formulas or valid earlier starting indices are also acceptable.

  1. Recursive: \(f(1)=3,\quad f(n+1)=f(n)+2\)
    Explicit: \(f(n)=3+2(n-1)\)
    For integer indices \(n\ge1\).
  2. Recursive: \(f(2)=4,\quad f(n+1)=2f(n)\)
    Explicit: \(f(n)=4\cdot2^{n-2}\)
    For integer indices \(n\ge2\).
  3. Recursive: \(f(6)=23,\quad f(n+1)=f(n)-4\)
    Explicit: \(f(n)=23-4(n-6)\)
    For integer indices \(n\ge6\).
  4. Recursive: \(f(1)=1,\quad f(n+1)=3f(n)\)
    Explicit: \(f(n)=3^{n-1}\)
    For integer indices \(n\ge1\).
  5. Recursive: \(f(3)=8,\quad f(n+1)=\frac12f(n)\)
    Explicit: \(f(n)=8\left(\frac12\right)^{n-3}\)
    For integer indices \(n\ge3\).
  6. Recursive: \(f(6)=7,\quad f(n+1)=f(n)+2\)
    Explicit: \(f(n)=7+2(n-6)\)
    For integer indices \(n\ge6\).
  7. Recursive: \(f(2)=40,\quad f(n+1)=f(n)-4\)
    Explicit: \(f(n)=40-4(n-2)\)
    For integer indices \(n\ge2\).
  8. Recursive: \(f(2)=16,\quad f(n+1)=\frac14f(n)\)
    Explicit: \(f(n)=16\left(\frac14\right)^{n-2}\)
    For integer indices \(n\ge2\).
  9. Recursive: \(f(17)=5,\quad f(n+1)=f(n)+\frac53\)
    Explicit: \(f(n)=5+\frac53(n-17)\)
    For integer indices \(n\ge17\).

Additional learning resources

Resource and direct linkWhat it supportsScope
The Organic Chemistry Tutor — Domain and Range of a Function From a GraphWorked graph-reading examples with interval notation and endpoint inclusion.A refresher for Set 2–9; it does not use the water-park context.

Teacher’s review of the source packet

No serious mathematical or instructional errors identified in Section 3.4. The initially unnumbered pool graph is intentional; Part II supplies the information needed to establish its scales. Go 18 is an arithmetic pattern with difference \(\frac53\) per index step; the answer key reflects the skipped indices.

Coverage — Section 3.4

Packet componentSkills supportedWhere taught
Main 1 · p. 16Interpret starting amounts, rates, emptying times, and a crossingIn class; numbered water-park graph
Main 2–3 and 6 · p. 17Write a linear draining rule; interpret coefficients; label graph scalesIn class; Dayne’s and Aly’s worked models
Main 4–6 · p. 17Algebraic versus contextual domain/range, units, endpoint inclusionIn class
Main 7–10 · p. 17Known input versus known output; equal amounts; compare graph heightsIn class; evaluation, solving, and intersection examples
Ready 1 · p. 18Linear/exponential changes, graph shapes, intercepts, domain and rangeSection 2; sample comparison answer
Set 2–9 · pp. 18–19Segments, rays, lines, curves, excluded endpoints and horizontal boundsSection 3; answer key and link to Section 3.2 reminders
Go 10–14 and 17 · p. 20Arithmetic/geometric explicit and recursive rules; non-1 starting indicesSection 4; answer key and link to Section 3.2 reminders
Go 15–16 and 18 · p. 20Skipped indices, per-step differences, fractional differenceSection 4; answer key with correct index steps

Source: MVP, Secondary Mathematics One, Module 3: Features of Functions (May 2016), Section 3.4, printed pp. 16–20, and its teacher notes. The in-class lesson uses the packet’s Aly-and-Dayne example; the pool diagrams recreate its starting graph and then add numbered axes. The Ready comparison is a sample answer, and the homework keys refer to the packet’s exercises. Mathematical notation needs an internet connection to load its renderer.

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